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double triple quad functions

 
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double triple quad functions, double triple quad
Mo821
post 11 Dec, 2005 - 01:07 PM
Post #1


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1. take 4 arguments type double ( could be passed by valur or reference
2. computes double (twice number) triple 3 ( three times) and quadruple (4 times)
3. uses 2nd, 3rd, and 4th arguments to "return" the double, triple, and quad.

B. 1.enter number
2. call yourdoubletriplequad function with numbers in first argument
3.print to screen double,triple,and quad values of entered number

# include <iostream>
using namespace std;

int doubleTripQuad (double, double&, double&, double&);

int main ()

{
double dbl, dbl2, dbl3, dbl4;
cout << "Please enter a number: ";
cin >> dbl >> dbl2 >> dbl3 >> dbl4;

return 0;
}

int doubleTripQuad (double dbl, double& dbl2, double& dbl3, double& dbl4)

{
dbl = 1 * 1;
dbl2 = 1 * 2;
dbl3 = 1 * 3;
dbl4 = 1 * 4;
}

your help in fixing this would be most appreciated
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Amadeus
post 11 Dec, 2005 - 02:01 PM
Post #2


g++ -o drink whiskey.cpp

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Joined: 12 Jul, 2002
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CODE

# include <iostream>
using namespace std;

double doubleTripQuad (double, double &, double &, double &);

int main ()

{
double dbl, dbl2, dbl3, dbl4;
cout << "Please enter a number: ";
cin >> dbl;
doubleTripQuad(dbl,dbl2,dbl3,dbl4);
cout<<"The original value was "<<dbl<<" and the returned values are "<<dbl2<<","<<dbl3<<","<<dbl4<<endl;
return 0;
}

double doubleTripQuad (double dbl, double &dbl2, double &dbl3, double &dbl4)

{
dbl2 = dbl  * 2;
dbl3 = dbl  * 3;
dbl4 = dbl * 4;
}

As an FYI, you had already opened a thread with this topic...I'll delete that one, but in the future, please try to keep all related material to the original thread.
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damoun
post 13 Dec, 2005 - 05:51 AM
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Joined: 6 Aug, 2005
Posts: 36
I am not really sure what you are trying to do but note that:

1) your function, doubleTripQuad(), is declared to be returning an int value, so in the fuction body you must have a return statment (an expressin following the keyword return).
note that if you omit the return statment most compilers will issue an error, but some will not and will return a random value.
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damoun
post 13 Dec, 2005 - 05:54 AM
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my bad, your fuction is returning a double.
if your function will only modify the vale of some varibles in the calling function, the the return type of the function should be declared void.
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Amadeus
post 13 Dec, 2005 - 06:30 AM
Post #5


g++ -o drink whiskey.cpp

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Geez, I must be getting sleepy while posting these days...that two mistakes in two days! smile.gif

damoun is correct, the return value of the function should have been modified to void...can't believe I misssed making that change. smile.gif
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