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According to simpsons 3/8 rule there must be atleast 3 intervals which means atleast 4 values of x.
If n is the no of intervas
If the user enters n<3 give an error mess and exit.
If n>=3 except x's upto n+1
Tell the user to enter the function y(see note).
then calculate y0,y1,.....yn[use arrays]
The rule says that
xn
⌡ y dx=3h/8[y0+3y1+3y2+2y3+....+2yn-3+3yn-2+3yn-1+yn]
x0
[⌠-Integration]
to do this you have to have an array with values [1,3,3,2]
go on multiplying them to y0,y1,...yn-4 in a cyclic loop.
Then do this 2yn-3+3yn-2+3yn-1+yn and add them all.
so you will be getting the sum in the bracket.
you know h(accept it from user).
Hence you will get the result.
[
Note:-
when you get the function y from user store it in a string.
You need to write a evaluation tree to find the values of y0,y1,..yn
for the values of x0,x1,..xn
]
This post has been edited by poke_blade: 2 May, 2006 - 11:40 PM
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2 May, 2006 - 07:14 AM
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