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Reversing an Integer

 
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Reversing an Integer
LogicCrusher
post 3 Oct, 2006 - 06:52 AM
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I am trying to write a code that will read an integer and print it out in reverse order.
So far the code prints strange characters (smiley faces…).
Why would it do that?
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Jayman
post 3 Oct, 2006 - 06:54 AM
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To answer you question you are going to need to post the code.
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LogicCrusher
post 3 Oct, 2006 - 07:48 AM
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QUOTE(jayman9 @ 3 Oct, 2006 - 07:54 AM) *

To answer you question you are going to need to post the code.


I had to redo the code because I didn’t save it first time.
Here is the code, if you type more than nine characters it will print crazy stuff.
I am using dev c++ compiler.

CODE
#include <iostream>
#include <string>

using namespace std;

int main()
{

char ch[20],ch1[20];
int i,j;
cout<<"enter the string ";
cin>>ch;
for( i=0;ch[i]!='\0';i++)
{
}
for( j=0,i-=1;i>=0;j++,i--)
{
ch1[j]=ch[i];
}
cout<<"\n"<<"the reverse string is "<<ch1;

    system("pause");
    return 0;
}


This post has been edited by Dark_Nexus: 3 Oct, 2006 - 09:02 AM
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frog
post 3 Oct, 2006 - 10:14 AM
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first of all in the second for loop you are updating the value of i in the intialization statement . that doesnt make any sense .also you should use a loop to take in the values in the character array rather than cin. next the garbage values you are getting are because there in no null character at the end of the array ch1 . just a little bit of modifications in the program and it'll run fine smile.gif
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born2c0de
post 4 Oct, 2006 - 06:14 AM
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printf("I'm a %XR",195936478);

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Actually, it's not meant to be done in this way.
Use the % operator to get the remainder after dividing by 10 to keep extracting the rightmost digit of the number.
Print the Extracted Digit.
Then divide the number by 10 and repeat the process.

Also remember that if number%10 results in a zero, keep dividing it by 10 till it's not.

Try writing the code, and post it here.
If you can't figure it out, we'll help you.
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frog
post 4 Oct, 2006 - 06:31 AM
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you were reversing an integer??? ohk i just read ur code and that asked the user to enter a string . anyways the method suggested by born2c0de is correct . work on that and i u face a problem feel free to post again
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santoshbb
post 12 Dec, 2006 - 11:08 PM
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QUOTE(frog @ 4 Oct, 2006 - 07:31 AM) *

you were reversing an integer??? ohk i just read ur code and that asked the user to enter a string . anyways the method suggested by born2c0de is correct . work on that and i u face a problem feel free to post again


The below program does the reverse int

CODE

#include<stdio.h>
int main()
{
        int num = 1234,resnum;
        resnum = reverse_num(num);
        printf("The reverse num is %d",resnum);
}

int reverse_num(int num)
{
        int tmp,tmp1,final_num=0;
        tmp = num;
        while(tmp)
        {
                tmp1 = tmp%10;
                tmp = tmp/10;
                final_num = (final_num *10)+tmp1;
        }
                return(final_num);
}
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eXceed69
post 12 Dec, 2006 - 11:34 PM
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Kindly used the [code] tag here...seems you used a function but this type program is not complex enough to had a function..and the main function had no return 0 when it is declare as int main....biggrin.gif
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shakti8ie
post 14 Dec, 2006 - 01:19 AM
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CODE

/*Reversing a number using string function*/

#include <iostream>
#include <string>

using namespace std;


int main()
{
    cout<<"Enter a number: ";
    int num;
    cin>>num;

    char buffer[10];//limitation
    itoa(num,buffer,10);
    strrev(buffer);
    num=atoi(buffer);
    
    cout<<endl<<"On reversing: "<<num<<endl;
}


I think this is one way to reversing a number...it has a limitation to work for upto 10 digit numbers...to accommodate bigger nums u have to change the size of array buffer[...]

This post has been edited by shakti8ie: 14 Dec, 2006 - 01:22 AM
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