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summation and functions

 
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summation and functions
leachrj
10 Dec, 2006 - 03:32 PM
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this program keeps giving me errors that i am using too many arguments in function term
i am attaching the assignment page someone please help.

CODE

#include <stdio.h>
#include <math.h>
long factorial(int n)
{
  int x;
  int fact = 1;
  for (x=1; x<=n; x++)
    fact = x*fact;
  return(fact);
}
float term(int n)
{
  return((pow(-1,n))*(1/factorial(n)));
}
int main()
{
  int j,n,d;
  int sum = 0;
  int i;
  printf("Enter n\n");
  scanf("%d",&n);
  
  for (j=0; j<=n; j++)
    sum += term(n,j);

  printf("Result = %d\n",sum);
  
  scanf("%i",&i);
  return(0);
}



Attached File(s)
Attached File  assign5.pdf ( 59.79k ) Number of downloads: 60
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gordo
RE: Summation And Functions
10 Dec, 2006 - 03:38 PM
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in this line...

for (j=0; j<=n; j++)
sum += term(n,j);

you can only pass n or j, not both.

sum += term(n);
//or
sum += term(j);

you decide which.
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leachrj
RE: Summation And Functions
10 Dec, 2006 - 04:00 PM
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i changed the line for which you said but now i am getting 0 for the answer what is happening i am desperate help
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eXceed69
RE: Summation And Functions
10 Dec, 2006 - 05:33 PM
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your returning so many value without a function to catch it,

CODE
sum += term(n[j]);


and just create a 2 catch onyour main function.
CODE

#include <stdio.h>
#include <math.h>

long factorial(int n)
{
int x;
int fact = 1;
for (x=1; x<=n; x++)
fact = x*fact;
return(fact);
}



float term(int n)
{
return((pow(-1,n))*(1/factorial(n)));
}


int main()
{

int j,n,d;
int sum = 0;
int i;
printf("Enter n\n");
scanf("%d",&n);

for (j=0; j<=n; j++)
{
sum += term(n[j]);

printf("Result = %d\n",sum);

scanf("%i",&i);
}
return(0);

}



This post has been edited by eXceed69: 10 Dec, 2006 - 05:56 PM
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Dark_Nexus
RE: Summation And Functions
10 Dec, 2006 - 05:46 PM
Post #5

or something bad...real bad.
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CODE

for (j=0; j<=n; j++)
{
sum += term(n[j]);

printf("Result = %d\n",sum);

scanf("%i",&i);
return(0);

}


this shouldn't compile because you are missing a } bracket.
also, the last for loop in your main function includes a return inside of the for loop, meaning that the for loop will only iterate once, and then it will return 0;
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shakti8ie
RE: Summation And Functions
14 Dec, 2006 - 02:24 AM
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CODE

#include <stdio.h>
#include <math.h>

long factorial(int n)
{
  int x;
  int fact = 1;
  for (x=1; x<=n; x++)
    fact = x*fact;
  return(fact);
}
float term(int n)
{
  return((pow(-1,n))*(1/(float)factorial(n)));
}
int main()
{
  int j,n,d;
  float sum = 0.0;

  printf("Enter n\n");
  scanf("%d",&n);
  
  for (j=0; j<=n; j++)
    sum += term(j);

  printf("Result = %f\n",sum*factorial(n));
  
  return(0);
}


Hi,

this code should work...the problem was u have to some typecasting while returning value from term()...this is the reason why u r getting 0 as output...again print the result as sum*factorial(n)...put the argument of term() as j in the for loop...right?
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