Write a program to grade a math exam. The answer sheet is in the following format:

10 + 15 = 25
30 – 1 = 28
6 * 2 = 12
10 / 3 = 3 ... 2
6 / 3 = 2 ... 0
3 x 2 = 6

Each calculation occupies a line. All calculations involve non-negative integers only. The result of a division consists of the quotient and the remainder, separated by three dots (as in lines 4 and 5 above). The remainder will be displayed even if it is zero (as in line 5 above). The output of your program should be in the following format:

1) 10 + 15 = 25
Correct.
2) 30 – 1 = 28
Incorrect. Answer is 29.
3) 6 * 2 = 12
Correct.
4) 10 / 3 = 3 ... 2
Incorrect. Answer is 3 ... 1.
5) 6 / 3 = 2 ... 0
Correct.
6) 3 x 2 = 6
Correct.
Your score: 4 out of 6

You don’t know how many questions there are in the test. Neither is known the order of these questions. In addition, either ‘x’/‘X’ or ‘*’ might be used for multiplication. The input file is c:\temp\test.txt and the result should be displayed on screen.

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Well the good news is that you don't need to write a complicated expression parser or do any infix to postfix conversion etc.. each line has a given format

[0-9]+' '[+-/*xX]' '[0-9]+' = '([0-9]+|[0-9]+' ... '[0-9])

so all you need to do is use a basic tokenizer (there are some examples in the snippets section) to serperate the expresions into tokens (using a space as the delineator). you know that the first three should be number, operation, number... determine the operation, preform that on the two numbers, and then check the answer.

Read each line, check the symbol after the first space or behind the first number, then perform that operation on both the numbers.

Use getline to get each line. You can sort through strings like stringname[position] or convert them to .c_str()

this is what i had so far. dont feel right at all...... somebody help me...



#include <iostream>
#include <string> //Pre-defined string data type
#include <iomanip> //output manipulators
#include <fstream> //File input/output
using namespace std;

int answer;
int num;
int sum;
int counter, numofcorrect, numofnotcorrect;
char ch1, ch2, ch3, ch4, ch5, correctornot;


int main()
{
ifstream data;
data.open("c:\temp\test.txt"); //open the input file.

while (!data.eof())
{
data >> num;
sum += num;
count++;
cout << "number = " << num << "count =" << count << "sum=" << sum <<endl;

}

switch (data)
{
case "+";
data >> num1 >> num2

cout << "10" << "+" << "15=" << num1+num2 << endl;
count++;

break;

case "-";
data >> num
cout << "30" << "-" << "1=" << num1+num2 << endl;
count++;

break;

case "*":
case "x":
case "X":
data >> num
cout << "6" << "*" << "2=" <<num1+num2 << endl;

cout << "you score:" << << "out of" << count << endl;


return 0;

}

well no, it doesn't seem right.
First off the file should have lines like "8 + 7 = 16" or "## op ## = ##" where the "##" is an number, "op" is an operation {+-*/xX}. If this is so, the code:
makes no sence? This would be grate if you had to take in a bunch of numbers in a file and print thier some, or find thier average or something.



The code would have a line something like the above... of course you need to think a little more because sometimes the line will look like "## / ## = ## ... ##".