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implementation

 
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implementation, c++
prebz
15 Mar, 2007 - 03:21 AM
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an aproximate value of pi can be calculated using the series given below

Pi = 4[ 1-1/3+1/5-1/7+1/9...+((-1)powerof n )2n+1]

Write a c++ program to calculatethe approximate value of pi using this series.The program takes an input n that that determines the number of terms in the approximation of the value pf pi and outputs the approximation .Includes a loop that allows the user top repeat this calculation for new values n until the user says she or he wants to end the program.
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NickDMax
RE: Implementation
15 Mar, 2007 - 03:38 AM
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read the rules... we need to see some good-faith code to show that you have tried to solve the problem.

The program is a basic loop, you even have the formula (though I think it has a mistake in it ((-1)^n)/(2n+1) ). just make a for-loop to sum up the inner terms, then multiply that sum by 4...
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born2c0de
RE: Implementation
16 Mar, 2007 - 10:19 PM
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printf("I'm a %XR",195936478);
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And don't iterate too many times.
At a particular point, the result is out of range for float and double data types.
This results in incorrect answers.
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