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Using variables in filenames

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Using variables in filenames

Trake	2 Aug, 2007 - 12:57 PM Post #1
D.I.C Head Joined: 29 Jun, 2007 Posts: 60 My Contributions	Hi all, Im trying to write a program that automatically creates files with names like: example1.txt; example2.txt etc. up to a point determined by the code. so far I have the following: CODE #include <iostream> #include <fstream> using namespace std; int fileCount; int fileTotal = 10; int main () { for (fileCount = 0; fileCount < fileTotal; fileCount++){ ofstream myfile; myfile.open ("example" + fileCount + ".txt"); myfile << "Writing this to a file.\n"; myfile.close(); } return 0; } But this wont even compile as fileCount is an int, I tried changing this to char or string but this wont work. Thanks in advance for the help. Trake
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PennyBoki	RE: Using Variables In Filenames 2 Aug, 2007 - 04:06 PM Post #2
system("revolution"); Joined: 11 Dec, 2006 Posts: 2,009 Thanked: 5 times Dream Kudos: 500 Expert In: Java,C++,C My Contributions	Hi, so I guess you just need to convert an int into a string. HERE is an example where such function is implemented. Hope it helps. just the function: CODE template<typename T> string toString(const T& x) { ostringstream oss; oss << x; return oss.str(); } but you have to CODE #include <sstream> for this I believe.
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Trake	RE: Using Variables In Filenames 3 Aug, 2007 - 04:37 AM Post #3
D.I.C Head Joined: 29 Jun, 2007 Posts: 60 My Contributions	Thanks for the quick reply it looks about right, only I want to change a char to an int not a string. I thought maybe I could do something like: CODE char fileStart[8] {e, x, a, m, p, l, e} char fileExtension[4]{., t, x, t} char fileName[12] And then change fileCount to a char and then make CODE fileStart[7] = fileCount followed by CODE fileName[0] = fileStart[0]; fileName[1] = fileStart[1]; etc. is this possible?
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PennyBoki	RE: Using Variables In Filenames 3 Aug, 2007 - 12:51 PM Post #4
system("revolution"); Joined: 11 Dec, 2006 Posts: 2,009 Thanked: 5 times Dream Kudos: 500 Expert In: Java,C++,C My Contributions	QUOTE(Trake @ 3 Aug, 2007 - 05:37 AM) Thanks for the quick reply it looks about right, only I want to change a char to an int not a string. I thought maybe I could do something like: CODE char fileStart[8] {e, x, a, m, p, l, e} char fileExtension[4]{., t, x, t} char fileName[12] And then change fileCount to a char and then make CODE fileStart[7] = fileCount followed by CODE fileName[0] = fileStart[0]; fileName[1] = fileStart[1]; etc. is this possible? I don't think that's possible because you are trying to convert an int into char with the assignment operator. I ask you why char and not string? This post has been edited by PennyBoki: 3 Aug, 2007 - 12:52 PM
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no2pencil	RE: Using Variables In Filenames 3 Aug, 2007 - 12:56 PM Post #5
My fridge be runnin OH NOEZ! Joined: 10 May, 2007 Posts: 6,451 Thanked: 66 times Dream Kudos: 2425 Expert In: Goofing Off My Contributions	I would use sprintf & dump everything into a buffer variable.
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Trake	RE: Using Variables In Filenames 3 Aug, 2007 - 01:57 PM Post #6
D.I.C Head Joined: 29 Jun, 2007 Posts: 60 My Contributions	I said char simply as I was trying to keep the code as simple as I can and as streamlined so that I can use it to create a lot of files ie about 1000 or more.
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PennyBoki	RE: Using Variables In Filenames 3 Aug, 2007 - 02:30 PM Post #7
system("revolution"); Joined: 11 Dec, 2006 Posts: 2,009 Thanked: 5 times Dream Kudos: 500 Expert In: Java,C++,C My Contributions	QUOTE(Trake @ 3 Aug, 2007 - 02:57 PM) I said char simply as I was trying to keep the code as simple as I can and as streamlined so that I can use it to create a lot of files ie about 1000 or more. And I said string for this function here QUOTE myfile.open ("example" + fileCount + ".txt"); where instead of fileCount which is an int there would be some variable that's a string in order to use that open() function.
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