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c--
4 Feb, 2008 - 09:18 PM
Post #1

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what does this means...?

int main( int argc, char* args[] )

Why do some people add those parameters there?
I know you are declaring an integer argc, and an array (args[]) pointer of type char.

But where can I use it??
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WXY
RE: Main
4 Feb, 2008 - 09:52 PM
Post #2

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They are used for command line parameters to your program. Let's say your program is named "foo.exe". Those two paramiters enables you to receive options via command line options eg: "foo.exe -someOption someValue"
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Nayana
RE: Main
4 Feb, 2008 - 10:16 PM
Post #3

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int argc is a number containing the number of elements in the array char* args[].

It's short for "argument count" and "arguments". In this case, as WXY stated, the arguments are the command line arguments.

A parameter and an argument in a function declaration are the same thing.
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born2c0de
RE: Main
5 Feb, 2008 - 10:36 AM
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Not many people know this, but main() also accepts a third parameter which contains all the environment variables.

Check out this example I wrote:
CODE
#include <iostream>
#include <cctype>

using namespace std;

int main(int argc,char** argv,char **env)
{
    int i=0;
    
    while(*(env[i++]))
    {
        cout<<"COUNT = "<<i<<" = "<<env[i]<<endl<<endl;
    }

  

  return 0;
}
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no2pencil
RE: Main
5 Feb, 2008 - 10:44 AM
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QUOTE(c-- @ 4 Feb, 2008 - 10:18 PM) *

what does this means...?

int main( int argc, char* args[] )

Why do some people add those parameters there?
I know you are declaring an integer argc, and an array (args[]) pointer of type char.

But where can I use it??

http://www.dreamincode.net/forums/showtopic30387.htm
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c--
RE: Main
5 Feb, 2008 - 08:25 PM
Post #6

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Thanks for the replies. smile.gif
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