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input date, month, and year, then display the week and day

 
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input date, month, and year, then display the week and day, teach me
jakee
post 10 Mar, 2008 - 02:52 AM
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hello!!

thanks for those people who reply to my previous post. i hope you can still help me.:-) can you please write a code about inputing the date, month, year, and display the week and day. and the if the user input three zero's. it will display already the result.

for example:

input:

31 02 2000

23 01 2001

13 12 2003

0 0 0

output:
monday 234

wednesday 231

saturday 132

just show me some codes and i'll understand it..

thanks!
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NickDMax
post 10 Mar, 2008 - 11:24 AM
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Dream.In.Code has a policy by which we prefer to see a good faith effort on your part before providing source code for homework assignments. Please post the code you have written in an effort to resolve the problem, and our members would be happy to provide some guidance. Be sure to include a description of any errors you are encountering as well.

Post your code like this: code.gif

Thanks.
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captainhampton
post 10 Mar, 2008 - 11:53 AM
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Do you have anything that you have attempted to at least try? Post some attempts at this material and we will be more than willing to help you out.
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jakee
post 10 Mar, 2008 - 05:54 PM
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CODE
#include<iostream>
#include<cstdlib>
using namespace std;


int Calendar;

int dd, mm, yy;

int main()
{

    do
    {
        cout << "Enter Day: " << endl;
        cin >> dd;
        cout << "Enter Month: " << endl;
        cin >> mm;
        cout << "Enter Year: " << endl;
        cin >> yy;

    }
    while(dd > 0 && mm > 0 && yy > 0);

    return 0;
}


this is the code i made but it is incomplete. i do not know the formula in getting the number of days and the day itself.
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zmikeb
post 10 Mar, 2008 - 07:25 PM
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here's a start:
CODE
    int months[12] = { 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 }
    if( yy / 4 == 0 )
        months[1] = 29;
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jakee
post 11 Mar, 2008 - 05:52 PM
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QUOTE(zmikeb @ 10 Mar, 2008 - 08:25 PM) *

here's a start:
CODE
    int months[12] = { 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 }
    if( yy / 4 == 0 )
        months[1] = 29;



can you please explain to me. thanks!
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zmikeb
post 11 Mar, 2008 - 07:07 PM
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well, this is just the declaration of an array that holds the days of each month of the year.....if it is a leapyear, february has 29 days.
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zmikeb
post 11 Mar, 2008 - 07:12 PM
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CODE
#include<iostream>
#include<cstdlib>
using namespace std;


int calendar;

int dd, mm, a = 0;
int yy;

int main()
{


        cout << "Enter Day (dd, **, ****): " << endl;
        cin >> dd;
        cout << "Enter Month (**, mm, ****): " << endl;
        cin >> mm;
        cout << "Enter Year (**, **, yyyy): " << endl;
        cin >> yy;

    int months[12] = { 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 };
    if( yy % 4 == 0 )
        months[1] = 29;
    for( int i = mm-1; i > 0; i-- )
    {
        a += months[i-1];
    }
    cout << a + dd; //outputs the day of the year

    return 0;
}


This shows the day of the year it is. Thats all I'm helping you with. Besides, I dont know how to show the day of the week...
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jakee
post 12 Mar, 2008 - 05:35 PM
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QUOTE(zmikeb @ 11 Mar, 2008 - 08:12 PM) *

CODE
#include<iostream>
#include<cstdlib>
using namespace std;


int calendar;

int dd, mm, a = 0;
int yy;

int main()
{


        cout << "Enter Day (dd, **, ****): " << endl;
        cin >> dd;
        cout << "Enter Month (**, mm, ****): " << endl;
        cin >> mm;
        cout << "Enter Year (**, **, yyyy): " << endl;
        cin >> yy;

    int months[12] = { 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 };
    if( yy % 4 == 0 )
        months[1] = 29;
    for( int i = mm-1; i > 0; i-- )
    {
        a += months[i-1];
    }
    cout << a + dd; //outputs the day of the year

    return 0;
}


This shows the day of the year it is. Thats all I'm helping you with. Besides, I dont know how to show the day of the week...


can you please refer to my code.

CODE
#include<iostream>
#include<cstdlib>
using namespace std;


int DetermineDayWeek(int, int, int);

int dd, mm, yy, a = 0;
int main()
{
    do
    {
        cout << "Enter Day: " << endl;
        cin >> dd;
        cout << "Enter Month: " << endl;
        cin >> mm;
        cout << "Enter Year: " << endl;
        cin >> yy;

    }
    while(dd > 0 && mm > 0 && yy > 0);
    if(dd == 0 && mm == 0 && yy == 0)
    {
        DetermineDayWeek(dd, mm, yy);
    }
    return 0;
}

int DetermineDayWeek(int dd, int mm, int yy)
{
    
    int months[12] = { 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 };
    
    if( yy % 4 == 0 )
    {
        months[1] = 29;
    }

    for(int i = mm-1; i > 0; i--)
    {
        a += months[i-1];
    }
    cout << a + dd << endl;
    return 0;
}


thanks!
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zmikeb
post 12 Mar, 2008 - 07:02 PM
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looks good so far. As for the day of the week, I suggest you look it up on google. They have really great explanations on how to do it.
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