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Shape using 0 and 1 alternatively...

 
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Shape using 0 and 1 alternatively...
bivunlim
post 12 Mar, 2008 - 11:12 PM
Post #1


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Joined: 12 Mar, 2008
Posts: 1
Well...
Let me show u...
CODE

#include<stdio.h>
#include<conio.h>
void main()
{
int i,n,j,k;
clrscr();
printf("Plz enter the height of the Shape::");
scanf("%d",&n);
for(i=1;i<=n;i++)
{
    for(j=1;j<=i;j++)
    printf("*");
    printf("\n");
}
getch();
}


Using this code I can generate a shape like this...
0
00
000
0000
00000

But I wanna make a shape like this...
1
01
010
1010
10101

Thats means insted of each 0 I want to use 1 and 0 alternatively.

I want to know how...

Cud it be possible to introduce an array with 0 and 1 in it and print those value alternatively???
If yes, plz guide me how...
I'm a really novice in this language...
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no2pencil
post 12 Mar, 2008 - 11:20 PM
Post #2


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I would do something like the following:
cpp

    int prn=0;
    for(j=1;j<=i;j++) {
      printf("%d",prn);  // will print the current number
      if(prn==0) prn++; // if it's zero, make it 1
      else prn--; // otherwise, it's 1, so make it zero
    }
    printf("\n")
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