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Argc

 
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Argc, arguments
C++programming
7 May, 2008 - 06:45 AM
Post #1

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I understand that argc refers to the number of arguments passed to the program. I do not understand however, how to use this. I'm doing a mad lib program and I can not find anything really useful or relevant to what I am suppose to incorporate in the program. Do you always have to use it this way

cpp
 int main(int argc, char* argv[]) { 
   cout << "argc = " << argc << endl; 
   for(int i = 0; i < argc; i++) 
      cout << "argv[" << i << "] = " << argv[i] << endl; 
   return 0; 
}

with the i's? The example he showed us in class did not have that in it.

Any feedback would be greatly appreciated!
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Amadeus
RE: Argc
7 May, 2008 - 10:10 AM
Post #2

g++ -o drink whiskey.cpp
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i is simply an integer variable being used as a loop counter. the code you have above will loop through the argument list and print them.
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