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fahrenheit to celsius

fahrenheit to celsius, Online class

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debeth

7 Jul, 2008 - 01:01 PM

Post #1

New D.I.C Head

Joined: 7 Jul, 2008
Posts: 19

I am asking a very basic question. I just started this online class and well i am struggling.
How do i get the program to end if the user answers my propmt with a no.

cpp

//asignment 2 to convert temperatures
//Dee Rasnake C++ class
// July 1, 2008

#include <iostream>
#include <iomanip>
#include <string>

using namespace std;

int main()

{//Declare the variables
	double fairinput;
    double celsout;
	
	string input;
	string y = "y";

    string Bye = "BYE";

    cout << fixed << showpoint;
	
	//propt the user
	cout << "Welcome to the Temperature Converter" << endl;
	cout << "Enter Degrees in Fahrenheight:  ";
	cin >> fairinput;
	cout << endl;
	       celsout=(fairinput-32)*5/9;
		       cout << setprecision(2) << endl;
			   cout <<"Degress in Celsius is : " << celsout
			   << endl;
    cout << "Continue ? (y/n) :" ;
    cin >> input;
	cout << endl;
	if (input < y)
		cout << Bye << endl;
// I want it to close if they choose n
	
	else
		cout << "Enter degrees in Fahrenheit: ";
	cin >> fairinput;
	cout << endl;
	       celsout=(fairinput-32)*5/9;
		       cout << setprecision(2) << endl;
			   cout <<"Degress in Celsius is : " << celsout
			   << endl;[/color]	 
	return 

system("PAUSE"); //This is the only way i can get it to hold the screen..How Come???
}

I hope some one can help...It hard doing it online with little comprehension......thanks Dee

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gabehabe

RE: Fahrenheit To Celsius
7 Jul, 2008 - 01:03 PM

Post #2

Donkey DIC

Joined: 6 Feb, 2008
Posts: 5,556

Windows

Thanked: 99 times
Dream Kudos: 2650
Expert In: ruling the world.

My Contributions

First off, welcome to </d.i.c>

Second, please

Third, moved to the correct forum.

Fourth, changed to title to a more descriptive one.

And finally, here is a possible solution:

You could use a do/while loop, and use cin.get() to hold it open.

Here:

cpp

//asignment 2 to convert temperatures
//Dee Rasnake C++ class
// July 1, 2008

#include <iostream>
#include <iomanip>
#include <string>

using namespace std;

int main()

{//Declare the variables
	double fairinput;
    double celsout;

	char input; // make this a char

    cout << fixed << showpoint;

	//propt the user
	do {
        cout << "Welcome to the Temperature Converter" << endl;
        cout << "Enter Degrees in Fahrenheight:  ";
        cin >> fairinput;
        cout << endl;
               celsout=(fairinput-32)*5/9;
                   cout << setprecision(2) << endl;
                   cout <<"Degress in Celsius is : " << celsout
                   << endl;
        cout << "Continue ? (y/n) :" ;
        cin >> input;
        cout << endl;
	} while (input != 'n' && input != 'N');
    cin.get (); // more useful way of holding the window open
    return EXIT_SUCCESS; // successful execution
}

Hope this helps

This Post Was Helpful!

debeth

RE: Fahrenheit To Celsius
7 Jul, 2008 - 03:20 PM

Post #3

New D.I.C Head

Joined: 7 Jul, 2008
Posts: 19

I will post in the

CODE

----

but i thought this was the right forum???? C++ right...
please bear with me....i will figure it out thanksss DEE

QUOTE(gabehabe @ 7 Jul, 2008 - 02:03 PM)

First off, welcome to </d.i.c>

Second, please

Third, moved to the correct forum.

Fourth, changed to title to a more descriptive one.

And finally, here is a possible solution:

You could use a do/while loop, and use cin.get() to hold it open.

Here:

cpp

//asignment 2 to convert temperatures
//Dee Rasnake C++ class
// July 1, 2008

#include <iostream>
#include <iomanip>
#include <string>

using namespace std;

int main()

{//Declare the variables
	double fairinput;
    double celsout;

	char input; // make this a char

    cout << fixed << showpoint;

	//propt the user
	do {
        cout << "Welcome to the Temperature Converter" << endl;
        cout << "Enter Degrees in Fahrenheight:  ";
        cin >> fairinput;
        cout << endl;
               celsout=(fairinput-32)*5/9;
                   cout << setprecision(2) << endl;
                   cout <<"Degress in Celsius is : " << celsout
                   << endl;
        cout << "Continue ? (y/n) :" ;
        cin >> input;
        cout << endl;
	} while (input != 'n' && input != 'N');
    cin.get (); // more useful way of holding the window open
    return EXIT_SUCCESS; // successful execution
}

Hope this helps

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Delta_Echo	RE: Fahrenheit To Celsius 7 Jul, 2008 - 08:22 PM Post #4
D.I.C Regular Joined: 24 Oct, 2007 Posts: 439 My Contributions	MMO, take you shitty spam bot off the forum. Ass hole. Now, in response to the forums intent. I suggest using an if statement. Here is an Example: cpp #include <iostream> using namespace std; int main(){ int m_menu; cout << "Menu: "; cout << "\n\n1. Choice One\n"; cout << "2. Choice Two\n"; cout << "> "; cin >> m_menu; if ( m_menu == 1){ cout << "You chose One!\n"; cin.get(); return 1; } if ( m_menu == 2){ cout << "You chose Two!\n"; cin.get(); return 1; } else { cout << "You chose neither!\n"; return 1; } } You can also use the switch statement: CODE switch{ //Declaration of a switch case (value to check for): { Statement to execute} case (value to check for): {Statements} default {statements to execute if no other case was met!} } // End Hope that helps! Good Luck! :-)
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