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hello, vb code for generating armstrong number within the limit

sramya	23 Jul, 2008 - 01:31 PM Post #1
New D.I.C Head Joined: 22 Jul, 2008 Posts: 1 My Contributions	dim m,n,p,s,a,c,i as integer private sub command1_click() n=val(text1.text) m=val(text2.text) s=0 p=0 for i=n to m step 1 c=i while(c>0) a=c mod 10 p=aaa s=s+p wend if(s=i) then print i end if next i end sub i tried myself for armstrong generation-providing upperlimit and lowerlimit as input, and the armstrong numbers within the limit should display.but it's not been executed. can you help me please.
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SpiderSpartan	RE: Hello 24 Jul, 2008 - 10:40 AM Post #2
D.I.C Head Joined: 6 Feb, 2008 Posts: 66 Thanked: 3 times Dream Kudos: 25 My Contributions	have you tried stepping through the code to see what it's doing. The other thing I see here is "print i" I'd recommend setting some "text3.text = i" or "label1.caption = i"
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Locke37	RE: Hello 24 Jul, 2008 - 10:57 AM Post #3
I'm not a thief...I prefer the term TREASURE HUNTER! Joined: 20 Mar, 2008 Posts: 1,005 Thanked: 39 times Dream Kudos: 325 My Contributions	In the future... However, all the cool people () use these tags... *[code=vb]*Paste your code between these tags[/code] >>> NO 's This post has been edited by Locke37*: 24 Jul, 2008 - 10:58 AM
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