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Convert string

 
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Convert string
Nickshawn
26 Sep, 2008 - 11:04 AM
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I have something like this:
CODE

int main(int argc, char *argv[]) {

char buffer[512];

        if(argc>2)
        {
                buffer = argv[2];  // HOW??
        }
        else
        {
                puts("Not enough parameters!");
                return 0;
        }

How can i convert argv[2] to char buffer?
Also, what are the technical names for these two?
Thank so much!
Nick
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gabehabe
RE: Convert String
26 Sep, 2008 - 11:29 AM
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argv[2] is a pointer, so why not just use:
char *buffer = argv[2];

smile.gif
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Psionics
RE: Convert String
26 Sep, 2008 - 11:45 AM
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to elaborate on what gabehabe said, pointers allow us to send values 'by-reference' instead of 'by-value'. The difference is when you use pointers, you don't have to make a copy of a variable, and instead you can just change the actual variable.

you can use a pointer just like this:
cpp

// declare a variable
int x;

// declare a pointer
int* ptr;     // you can write this as int* ptr or int *ptr...same thing

// point the pointer to the address of x
ptr = &x    // the & means the 'address of'

// now you can use the pointer to change and display x
*ptr = 10;    // using the * 'dereferences' the pointer, showing the value

cout << "x = " << *ptr << endl;     // will display 10


I just made this incase you didn't understand pointers smile.gif
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Nickshawn
RE: Convert String
26 Sep, 2008 - 11:55 AM
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Nice! Thanks for the fast responce.
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Psionics
RE: Convert String
26 Sep, 2008 - 11:57 AM
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it's no problem, do you understand everything you need?
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Nickshawn
RE: Convert String
26 Sep, 2008 - 12:07 PM
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I'll never understand everything i need...but i understand pointers well!
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